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match 22 crypto 31 渗透 15 cs和msf 4 AES 1 RSA 25 ECC 1 Linux 2 Web 10 RCE 1 SSTI 1 ATT&CK红队实战 3 漏洞挖掘 2 md5绕过 1 Sql 6 变量覆盖 1 vulnhub 2
2024HSCCTF 2024HSCCTF
REAL_SIGN_INn1 = 1326609497911843361510707743883511137145750370453861649656351028925060019798402976795095307172344238127
2024-03-26 match
2024HSCCT
2023 ISCTF 2023 ISCTF
MISC签到关注公众号回复即可 CRYPTO七七的欧拉import gmpy2 import libnum e=8401285423075497989963572888601376313375827722858883767564499066
2023-12-14 match
ISCTF
2023 HECTF 2023 HECTF
Crypto大帝攻占福岛c="zpvepoudbsgcdqwvjgocqg|rxrqo|feviefsyx}szwt|skqfl?NKIZLYZUVfU|jslhyfzmiom…" print(len(c)) flag = '
2023-11-20 match
2023 HECTF
2023 NewStar WEEEK4 2023 NewStar WEEEK4
CryptoRSA Variation II题目 from secret import flag from Crypto.Util.number import * p = getPrime(1024) q = getPrime(1024)
2023-10-30 match
2023 NewStarCTF
2023 NewStarCTF Week3 2023 NewStarCTF Week3
CryptoRabin’s RSA题目 from Crypto.Util.number import * from secret import flag p = getPrime(64) q = getPrime(64) assert p
2023-10-25 match
2023 NewStarCTF
2023 NewStarCTF WEEK2 2023 NewStarCTF WEEK2
[TOC] Crypto滴啤题目 from Crypto.Util.number import * import gmpy2 from flag import flag def gen_prime(number): p = getP
2023-10-15 match
2023 NewStarCTF
2023 0xGame Week1 2023 0xGame Week1
CryptoVigenere题目 [TOC] 0dGmqk{79ap4i0522g0a67m6i196he52357q60f} 密钥game flag: 0xGame{79ad4e0522a0a67a6e19
2023-10-11 match
2023 0xGame
2023 NewStarCTF WEEK1 2023 NewStarCTF WEEK1
[TOC] cryptobrainfuck题目 ++++++++[>>++>++++>++++++>++++++++>++++++++++>++++++++++++>+++++++++++++
2023-10-11 match
2023 NewStarCTF
安洵杯全国精英赛2023 安洵杯全国精英赛2023
signinhttps://blog.csdn.net/figfig55/article/details/127283671 连分数逼近data3，得到data1,data2 #sage data3 = 1.4287076735720660
2023-06-11 match
安洵杯
2023陕西省网络安全技能大赛 2023陕西省网络安全技能大赛
Crypto奇怪的sar首先就是一个lcg，求出seed，seed就是p,q异或的值，还已知n=pq,然后找一个已知seed=p^q,n=pq的脚本分解n，然后RSA得flag lcg https://blog
2023-06-09 match
2023陕西省赛
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